217. Contains Duplicate
难度: 简单
刷题内容
原题连接
- https://leetcode.com/problems/contains-duplicate/
内容描述
Given an array of integers, find if the array contains any duplicates.
Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct.
Example 1:
Input: [1,2,3,1]
Output: true
Example 2:
Input: [1,2,3,4]
Output: false
Example 3:
Input: [1,1,1,3,3,4,3,2,4,2]
Output: true
解题方案
思路 1
利用set怎么可以这么简单。。。。
class Solution(object):
def containsDuplicate(self, nums):
"""
:type nums: List[int]
:rtype: bool
"""
return len(nums) != len(set(nums))
思路 2
或者先 sort 也可以
class Solution(object):
def containsDuplicate(self, nums):
"""
:type nums: List[int]
:rtype: bool
"""
nums.sort()
for i in range(len(nums)-1):
if nums[i] == nums[i+1]:
return True
return False
