56. Merge Intervals
难度:Medium
刷题内容
原题连接
- https://leetcode.com/problems/merge-intervals/
内容描述
Given a collection of intervals, merge all overlapping intervals.
Example 1:
Input: [[1,3],[2,6],[8,10],[15,18]]
Output: [[1,6],[8,10],[15,18]]
Explanation: Since intervals [1,3] and [2,6] overlaps, merge them into [1,6].
Example 2:
Input: [[1,4],[4,5]]
Output: [[1,5]]
Explanation: Intervals [1,4] and [4,5] are considered overlapping.
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/**
* Definition for an interval.
* struct Interval {
* int start;
* int end;
* Interval() : start(0), end(0) {}
* Interval(int s, int e) : start(s), end(e) {}
* };
*/
class Solution {
public:
vector<Interval> merge(vector<Interval>& intervals) {
vector<Interval> ans;
if(!intervals.size())
return ans;
sort(intervals.begin(),intervals.end(),[](Interval a, Interval b){return a.start < b.start;});
for(int i = 0;i < intervals.size() - 1;++i)
if(intervals[i + 1].start <= intervals[i].end)
{
intervals[i + 1].start = intervals[i].start;
intervals[i].end = max(intervals[i].end,intervals[i + 1].end);
intervals[i + 1].end = intervals[i].end;
}
else
ans.push_back(intervals[i]);
ans.push_back(intervals[intervals.size() - 1]);
return ans;
}
};
